Answer:
(x^2−2xy+y^2)−z^2
⇒[x(x−y)−y(x−y)]−z^2
⇒(x−y)(x−y)−z^2
⇒(x−y)^2−z^2
⇒[(x−y)+z][(x−y)−z]
⇒(x−y+z)(x−y−z)
8.6m questions
11.3m answers