Answer:
2 real zeros at x = - 2 , x = 1
Explanation:
f(x) = x² + x - 2
to find the zeros let f(x) = 0 , that is
x² + x - 2 = 0 ← in standard form
(x + 2)(x - 1) = 0 ← in factored form
equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
x + 1 = 0 ⇒ x = - 1
there are 2 real zeros , x = - 2 and x = 1