101k views
4 votes
How many zeroes (real or imaginary) does f ( x ) = x 2 + x − 2 have?

1 Answer

3 votes

Answer:

2 real zeros at x = - 2 , x = 1

Explanation:

f(x) = x² + x - 2

to find the zeros let f(x) = 0 , that is

x² + x - 2 = 0 ← in standard form

(x + 2)(x - 1) = 0 ← in factored form

equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 1 = 0 ⇒ x = - 1

there are 2 real zeros , x = - 2 and x = 1

User John Corry
by
7.4k points