Question

A student is making a solution of NaCl in water. If the student uses 6.24 grams of NaCl and enough water to make 6.62 liters of solution, what is the molarity of the student's salt solution?

Answer 1

0.0161 M

Step-by-step explanation:

To find the molarity of the NaCl solution, we need to use the formula:

Molarity (M) = moles of solute / liters of solution

First, we need to calculate the number of moles of NaCl in the solution. We can do this by dividing the mass of NaCl by its molar mass. The molar mass of NaCl is 58.44 g/mol.

moles of NaCl = mass of NaCl / molar mass of NaCl

moles of NaCl = 6.24 g / 58.44 g/mol

moles of NaCl = 0.1066 mol

Now we can use the formula for molarity:

Molarity (M) = moles of solute / liters of solution

Molarity (M) = 0.1066 mol / 6.62 L

Molarity (M) = 0.0161 M

Therefore, the molarity of the student's NaCl solution is 0.0161 M.