Answer:
0.790, or 79%.
Explanation:
If the probability of getting a two on a biased dice is 0.1, then the probability of not getting a two is 0.9.
We can use the binomial distribution to calculate the probability of getting a certain number of twos in 250 rolls of the dice. The formula for the binomial distribution is:
P(X = k) = C(n, k) * p^k * (1-p)^(n-k)
Where:
P(X = k) is the probability of getting exactly k twos
n is the number of trials (250 rolls)
k is the number of successes (getting a two)
p is the probability of success (0.1)
(1-p) is the probability of failure (0.9)
C(n, k) is the number of ways to choose k successes from n trials (n choose k)
To calculate the probability of getting exactly k twos in 250 rolls, we plug in the values for n, k, p, and (1-p) into the formula:
P(X = k) = C(250, k) * 0.1^k * 0.9^(250-k)
We can use a calculator or a software program to find the probabilities for different values of k. Here are some examples:
The probability of getting no twos (k = 0) is P(X = 0) = C(250, 0) * 0.1^0 * 0.9^250 = 0.057
The probability of getting exactly one two (k = 1) is P(X = 1) = C(250, 1) * 0.1^1 * 0.9^249 = 0.153
The probability of getting at least two twos (k >= 2) is the complement of the probability of getting zero or one two:
P(X >= 2) = 1 - P(X = 0) - P(X = 1)
= 1 - 0.057 - 0.153
= 0.790
Therefore, the probability of getting at least two twos in 250 rolls of the biased dice is approximately 0.790, or 79%.
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