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I need help with question 3 I need to find the rate at which the water is rising in cm/seconds

I need help with question 3 I need to find the rate at which the water is rising in-example-1

1 Answer

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Answer:

0.01 cm/min

Explanation:

The volume of oil in the tank is given by the formula:

V = l × w × h

where l, w, and h are the length, width, and height of the tank respectively.

Substituting the given values, we get:

V = 60 cm × 100 cm × 100 cm = 600,000 cm³

The rate at which the oil is being lost is given as 3.6 litres per hour. Since 1 litre = 1000 cm³, we can convert this to cubic centimeters per hour as follows:

3.6 litres/hour × 1000 cm³/litre = 3600 cm³/hour

To find the rate at which the oil level is falling, we need to divide the rate of oil loss by the surface area of the oil in the tank. Since the tank is rectangular and has a flat bottom, the surface area of the oil is simply the area of the top of the tank, which is:

A = l × w = 60 cm × 100 cm = 6000 cm²

Now, we can calculate the rate at which the oil level is falling as follows:

rate of oil loss ÷ surface area of oil = (3600 cm³/hour) ÷ (6000 cm²)

= 0.6 cm/hour

To convert this to cm/min, we simply divide by 60:

0.6 cm/hour ÷ 60 min/hour = 0.01 cm/min

Therefore, the rate at which the oil level is falling is 0.01 cm/min

User Miguel Febres
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