Question

1.6.1) Does the relationship in the table represents direct or inverse/indirect proportion?

1.6.2) Determine the value of a.
1.6.3) Determine the distance a car will travel using the first two values in the table.​

Answer 1

1.6.1) Inversely proportional

1.6.2) 0.6h

1.6.3) 120km

Explanation:

1.6.1)

Inversely proportional relationships are in the form of
`y=k/x`

`y=time=t`

`x=speed=v`

If we the relationship is inversely proportional,
`k` must be constant for all values.

`yx=k`

So we just have to check the value of
`yx` in all cases.

`20*3=60\\50*1.2=60\\80*0.75=60`

Hence relation is inversely proportional.

1.6.2)

`k=60, x=100, y=k/x\\`

∴
`y=60/100` ⇒
`y=0.6`

1.6.3)

Distance formula:

`v=s/t\\v*t=s\\s=(20*3) + (50*1.2)\\s=60 + 60\\s=120`