Answer:
(a) To write 9 N as a number in standard form, we need to express it as a number between 1 and 10 multiplied by a power of 10. To do this, we can divide 9 N by 10 until we get a number between 1 and 10:
9 N = 480 × 10^9
9 N ÷ 10 = 48 × 10^9
9 N ÷ 10^2 = 4.8 × 10^9
9 N ÷ 10^3 = 0.48 × 10^9
9 N ÷ 10^4 = 0.048 × 10^9
9 N ÷ 10^5 = 0.0048 × 10^9
Therefore, 9 N = 4.8 × 10^10.
(b) To write N as a product of powers of its prime factors, we can first factorize N:
480 × 10^9 = 2^5 × 3 × 5 × 10^9
Then, we can express 10^9 as 2^9 × 5^9 and substitute it in the factorization:
2^5 × 3 × 5 × 2^9 × 5^9 = 2^14 × 3 × 5^10
Therefore, N = 2^14 × 3 × 5^10.
(c) To find the largest factor of N that is an odd number, we need to remove all factors of 2 from the factorization of N. We can do this by dividing N by 2 as many times as possible:
N = 2^14 × 3 × 5^10
N ÷ 2 = 2^13 × 3 × 5^10
N ÷ 2^2 = 2^12 × 3 × 5^10
N ÷ 2^3 = 2^11 × 3 × 5^10
N ÷ 2^4 = 2^10 × 3 × 5^10
N ÷ 2^5 = 2^9 × 3 × 5^10
N ÷ 2^6 = 2^8 × 3 × 5^10
N ÷ 2^7 = 2^7 × 3 × 5^10
N ÷ 2^8 = 2^6 × 3 × 5^10
N ÷ 2^9 = 2^5 × 3 × 5^10
N ÷ 2^10 = 2^4 × 3 × 5^10
N ÷ 2^11 = 2^3 × 3 × 5^10
N ÷ 2^12 = 2^2 × 3 × 5^10
N ÷ 2^13 = 2 × 3 × 5^10
N ÷ 2^14 = 3 × 5^10
Therefore, the largest factor of N that is an odd number is 3 × 5^10.