Step-by-step explanation:
The balanced chemical equation for the reaction between sulfuric acid and potassium hydroxide is:
H₂SO4(aq) + 2KOH(aq) → K₂SO4(aq) + 2H₂O(l)
From the equation, we can see that 1 mole of H₂SO4 reacts with 2 moles of KOH. We can use this information to determine the number of moles of H₂SO4 and KOH present in the mixture before neutralization:
moles of H₂SO4 = 0.850 L x 0.400 mol/L = 0.34 mol
moles of KOH = 0.800 L x 0.250 mol/L = 0.20 mol
Since KOH is the limiting reagent, it will be completely consumed in the reaction. The number of moles of H₂SO4 that reacts with the KOH is given by:
moles of H₂SO4 reacted = 2 x moles of KOH = 0.40 mol
The remaining moles of H₂SO4 after neutralization is:
moles of H₂SO4 remaining = moles of H₂SO4 - moles of H₂SO4 reacted
moles of H₂SO4 remaining = 0.34 mol - 0.40 mol
moles of H₂SO4 remaining = -0.06 mol
Since the moles of H₂SO4 remaining is negative, it means that all of the H₂SO4 has reacted with the KOH and there is an excess of KOH. Therefore, the concentration of sulfuric acid remaining after neutralization is 0 M.