Question

6.0 mol NaOH can form

3.0 mol Na3PO4 while 9.0 mole H3PO4
can form 9.0 mol Na3PO4. What mass of
Na3PO4 forms?
Na3PO4: 164 g/mol
[?] g Na3PO4
Round your answer to the ones place.
g NasPO4

Answer 1

1) 492 grams Na3PO4

2) 1,476 grams Na3PO4

Step-by-step explanation:

6.0 mol NaOH forms 3.0 mol Na3PO4

9.0 mole H3PO4 forms 9.0 mol Na3PO4.

What mass of Na3PO4 forms?

1) 6.0 moles of NaOH

3.0 moles of Na3PO4 are formed. Convert thism into grams using the molar mass conversion factor: 164 g/mole

(3.0 moles Na3PO4)*(164 g/mole Na3PO4) = 492 grams

2) 9.0 moles of H3PO4

9.0 moles of Na3PO4 are formed. Again, use the molar mass conversion factor.

(9.0 moles Na3PO4)*(164 g/mole Na3PO4) = 1,476 grams Na3PO4