Question

The equation d=16t^2 gives the distance in feet that a golf ball falls in t seconds.How many seconds will it take the gol to drop to the ground from a height of 4 feet?64 feet?

Answer 1

We are given the following function of distance in terms of time:

`d=16t^2`

Where:

`\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}`

We are asked to determine the time when the distance is 4ft. To do that we will solve for "t". First, we will divide both sides by 16:

`(d)/(16)=t^2`

Now, we take the square root to both sides:

`\sqrt{(d)/(16)}=t`

Simplifying we get:

`(1)/(4)√(d)=t`

Now, we substitute the value of the distance:

`(1)/(4)√(4)=t`

Solving the operations:

`\begin{gathered} (1)/(2)=t \\ \\ 0.5=t \end{gathered}`

Therefore, the time is 0.5

The same procedure is used to determine the time for 64 feet.