Answer:
Explanation:
Because this problem is not easily solvable through factoring, we must use long division to find the answer.
_______________ x+7 | x3 + kx2 - 34x + 56
When performing long division on polynomials, we should try to cancel out the term with the greatest power first. So, we must figure out how many x's go into x3, because x is the first term of the first polynomial and x3 is the first term of the second polynomial. x*x2 = x3, so:
x2
_______________ x+7 | x3 + kx2 - 34x + 56
(-) x3 + 14x2
(k-14)x2 - 34x
Then, we see how many x's go into (k-14)x2. x*(k-14)x = (k-14)x2, so:
x2 + (k-14)x
_______________ x+7 | x3 + kx2 - 34x + 56
(-) x3 + 14x2
(k-14)x2 - 34x
(-) (k-14)x2 - 7kx - 98x
-7kx - 132x + 56= (-7k-132)x + 56
x*(-7k-132) = (-7k-132)x, so:
x2 + (k-14)x + (-7k-132)
_______________ x+7 | x3 + kx2 - 34x + 56
(-) x3 + 14x2
(k-14)x2 - 34x
(-) (k-14)x2 - 7kx - 98x
(-7k-132)x + 56
(-) (-7k-132)x - 7k - 924
-7k - 868
The answer is x2 + (k-14)x + (-7k-132) - [(7k-868)/(x+7)]