Answer:
The reaction between butanoic acid and ethanol produces ethyl butyrate and water, and the balanced chemical equation is:
Butanoic acid + Ethanol → Ethyl butyrate + Water
The molar mass of butanoic acid is 88.1 g/mol, and the molar mass of ethanol is 46.1 g/mol. The molar mass of ethyl butyrate is 116.2 g/mol.
To determine the amount of ethyl butyrate produced, we need to use stoichiometry and the given mass of butanoic acid to find the number of moles of butanoic acid, and then use the mole ratio to find the number of moles (and mass) of ethyl butyrate produced.
Calculate the number of moles of butanoic acid:
moles of butanoic acid = mass/molar mass = 7.00 g / 88.1 g/mol = 0.0795 mol
Use the mole ratio to find the number of moles of ethyl butyrate produced:
From the balanced equation, we see that 1 mole of butanoic acid reacts with 1 mole of ethanol to produce 1 mole of ethyl butyrate.
So, the number of moles of ethyl butyrate produced = 0.0795 mol (since we assume a 100% yield)
Calculate the mass of ethyl butyrate produced:
mass of ethyl butyrate = moles x molar mass = 0.0795 mol x 116.2 g/mol = 9.23 g
Therefore, 9.23 grams of ethyl butyrate would be synthesized if 7.00 grams of butanoic acid were reacted with excess ethanol, assuming a complete 100% yield.