Question

the solubility of sodium chloride at room room temperature is 35.8g of nacl per 135.8 g of solution and the density of this solution is 1.20g/ml. calculate the molarity of a saturated solution of nacl

Answer 1

5.41 M

Step-by-step explanation:

To calculate the molarity of a saturated solution of NaCl, we first need to calculate the amount of NaCl in the solution:

35.8 g of NaCl per 135.8 g of solution means that the mass of NaCl in the solution is:

mass of NaCl = 35.8 g

The density of the solution is 1.20 g/mL, so the volume of the solution can be calculated as:

volume of solution = mass of solution / density of solution

volume of solution = 135.8 g / 1.20 g/mL

volume of solution = 113.17 mL

Now we need to convert the volume of the solution to liters:

volume of solution = 113.17 mL = 0.11317 L

To calculate the molarity of the solution, we need to know the number of moles of NaCl in the solution. We can calculate this using the formula:

moles of solute = mass of solute / molar mass of solute

The molar mass of NaCl is 58.44 g/mol, so:

moles of NaCl = 35.8 g / 58.44 g/mol

moles of NaCl = 0.612 mol

Now we can calculate the molarity of the solution using the formula:

molarity = moles of solute / liters of solution

molarity = 0.612 mol / 0.11317 L

molarity ≈ 5.41 M