Question

Calculate the power of a 2057 Ω night light plugged into a 120 V source.

Answer 1

Lets write the data down:

R = 2057 Ω

V = 120 V

The power of the night light is given by:

`P=(V^2)/(R)`

Plug in the data in the formula:

`\begin{gathered} P=(120^2)/(2057) \\ P=(14,400)/(2057) \\ P\approx7.0W \end{gathered}`

The power of the night light is 7.0 W.