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when a mass m is hung on a certain ideal spring, the spring stretches a distance d. if the mass is then set oscillating on the spring, the period of oscillation is proportional to

User Hexagon
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Answer:

ω = (k / m)^1/2 proportionality for angular speed in SHM

f = ω / 2 * π

Since P = 1 / f the period is inversely proportional to ω

P proportional to m

P inversely proportional to k the spring constant

User Lolade
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