Question

In square abcd, BE=13 find BC

Answer 1

13sqrt{2}

Explanation:

let's assume one side of square is a;

diognal which is BD=

`a√(2)\\BE is BD/2=(a√(2))/(2)=13\\a√(2)=26\\a=26/√(2)=13√(2)`

BC=CD=DA=AB=a=13sqrt{2}