Answer:
Explanation:
We can use the standard normal distribution to solve this problem by standardizing the score.
z = (x - mu) / sigma
Where:
x = 70 (score we are interested in)
mu = 60 (mean score)
sigma = 7 (standard deviation)
z = (70 - 60) / 7 = 1.43
Using a standard normal distribution table or calculator, we can find the probability that z is greater than 1.43. The probability is approximately 0.0764.
Therefore, the probability that a randomly selected student scored more than 70 on the exam is 0.0764 (or about 7.64%).