Question

What is the standard equation of a circle whose center is (-3, 5) and radius is 2?

Answer 1

Explanation:
The standard equation of a circle with center (a, b) and radius r is:

(x - a)^2 + (y - b)^2 = r^2

Using the given values, we have:

(x - (-3))^2 + (y - 5)^2 = 2^2

Simplifying:

(x + 3)^2 + (y - 5)^2 = 4

Therefore, the standard equation of the circle is (x + 3)^2 + (y - 5)^2 = 4.

Answer 2

`(x + 3)^2 + (y - 5)^2 = 4`

Explanation:

`(x - h)^2 + (y - k)^2 = r^2`

`(x - (-3))^2 + (y - 5)^2 = 2^2`

`(x + 3)^2 + (y - 5)^2 = 4`