Question

Answer this for me!!

Answer 1

Option b is the right answer

Answer 2

We have divided the figure into 3 parts i.e. ; 2 rectangles and 1 triangle...

`\boxed{ \red { \mathfrak{Area\: of\: figure =l * b + l * b + (1)/(2) * b * h}}}`

We have the dimensions:

• l = 8 ft
• b = 7 ft
• l = 6 ft
• b = 2 ft
• h = 1 ft
• b = 2 ft

`\blue{ \sf{Area\: of\: figure = 8 * 7 + 6 * 2 + (1)/(2) * 2 * 1 }}`

`\blue{ \sf{Area\: of\: figure =56 + 12 + (1)/( \cancel2) * \cancel 2 }}`

`\blue{ \sf{Area\: of\: figure =56 + 12 + 1}}`

`\blue{ \sf{Area\: of\: figure =69 \: {ft}^(2) }}`

Hence, Option B is correct!!