Question

The area of a square is 500. If its width is one-fifth as long as its length is 4 times long, what is the new area?

A.100
B.400
C.500

Answer 1

Option A, 100 is the new area.

Step-by-step explanation:
Let's assume that the length of the square is x. Then, according to the problem, the width of the square is one-fifth as long as the length, which means the width is x/5. The area of the square is given as 500, which means:

x * x = 500

x^2 = 500

x = sqrt(500) = 10 * sqrt(5)

So, the length of the square is 10 * sqrt(5). Using this information, we can find the width:width = x/5 = (10 * sqrt(5))/5 = 2 * sqrt(5)

Now we can find the new area of the square by multiplying the new length and width:new area = (2 * sqrt(5)) * (10 * sqrt(5)) = 100

Therefore, the new area of the square is 100, which is option A.