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PLEASE HELP - WORTH 35 POINTS! In a game, each spinner is spun once. What is the probability of landing on an odd number for each spinner. Express your answer as a fraction.

PLEASE HELP - WORTH 35 POINTS! In a game, each spinner is spun once. What is the probability-example-1
User Ryangus
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Assuming that each spinner has an equal number of possible outcomes, let's consider the possible outcomes for each spinner:

Spinner 1:

Odd numbers: 1, 3, 5
Even numbers: 2, 4, 6
Spinner 2:

Odd numbers: 1, 3, 5
Even numbers: 2, 4, 6
Since we want the probability of landing on an odd number for each spinner, we need to find the probability of landing on an odd number for Spinner 1 and the probability of landing on an odd number for Spinner 2, and then multiply them together.

The probability of landing on an odd number for Spinner 1 is 3/6, or 1/2 (since there are 3 odd numbers and 6 total numbers).

The probability of landing on an odd number for Spinner 2 is also 1/2, for the same reason.

Therefore, the probability of landing on an odd number for each spinner is (1/2) x (1/2) = 1/4.

So the probability of landing on an odd number for each spinner is 1/4.
User Grochmal
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