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How many gallons each of ​15% alcohol and 10​% alcohol should be mixed to obtain 5 gal of ​14% ​alcohol?

User Cory Shay
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1 Answer

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Answer:

Step-by-step explanation:

Let x be the number of gallons of 15% alcohol to be mixed and y be the number of gallons of 10% alcohol to be mixed.

We can set up the following system of equations based on the information given:

x + y = 5 (the total volume of the mixture is 5 gallons)

0.15x + 0.1y = 0.14(5) (the amount of pure alcohol in the mixture is 0.14 times the total volume of the mixture)

Simplifying the second equation, we get:

0.15x + 0.1y = 0.7

Multiplying both sides by 10 to eliminate the decimals, we get:

1.5x + y = 7

Now we can solve the system of equations by substitution or elimination to find x and y. Here, we will use the substitution method.

Solving the first equation for y, we get:

y = 5 - x

Substituting this expression for y into the second equation, we get:

1.5x + (5 - x) = 7

Simplifying and solving for x, we get:

0.5x = 2

x = 4

Substituting this value for x into the expression for y, we get:

y = 5 - 4 = 1

Therefore, we need 4 gallons of 15% alcohol and 1 gallon of 10% alcohol to obtain 5 gallons of 14% alcohol.

User Jaxvy
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