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a gas at 300 k occupies 6.50 l at a pressure of 3.50 atm. what will its pressure be at 250 k if its volume is reduced to 4.80 l? please show work and what law you used

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Answer: You have the values of P1, V1, T1, T2, and V2. Plug in the numbers and get P2.

Explanation:

Work with the relation

P1V1 / T1 = P2V2 / T2 ⇒

P2 = (P1V1 / T1) (T2 / V2)

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