Each bus can carry 14 students and each van can carry 6 students.
Step-by-step explanation:
Let's assume that a van can carry 'v' students.
Let's assume that a bus can carry 'b' students.
Using this notation, we can set up the following system of equations:
For the first high school:
8v + 9b = 228
For the second high school:
4v + 5b = 124
We have two equations and two unknowns, so we can solve for 'v' and 'b'.
To do this, we can start by solving the second equation for 'b':
5b = 124 - 4v
b = (124 - 4v)/5
We can substitute this expression for 'b' into the first equation:
8v + 9((124 - 4v)/5) = 228
Multiplying both sides by 5 to eliminate the fraction:
40v + 9(124 - 4v) = 1140
Distributing the 9:
40v + 1116 - 36v = 1140
Simplifying:
4v = 24
v = 6
Substituting this value of 'v' into the equation for 'b':
5b = 124 - 4(6)
b = 14
Therefore, a van can carry 6 students, and a bus can carry 14 students.
So the answer is: Each bus can carry 14 students and each van can carry 6 students.