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Let f(x) = 3(x - 6)^2 + 1. What is the range of f? Express your answer with interval notation.
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Let f(x) = 3(x - 6)^2 + 1. What is the range of f? Express your answer with interval notation.

User Nitin Pawar
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2 Answers

5 votes
X is an element of [6,+ inf [
User Chitra Khatri
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f(x) = 3(x-6)²+1
This is an up-opening parabola with vertex (6,1).
Range: [1,+∞)
User Gaurav Bhavsar
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5.2k points
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