Question

The concentrations in the reaction 2A + B <-> 2C were measured at 500 K when the reaction reached equilibrium. Calculate the equilibrium constant for the

reaction. You may use a calculator. Concentration of A = 0.72 M Concentration
of B = 0.32 M Concentration of C = 0.12 M

Answer 1

The equilibrium constant (Kc) for the reaction is given by:

Kc = [C]²/([A]²[B])

Substituting the given values, we get:

Kc = (0.12)²/((0.72)²(0.32))

Kc = 0.00256/0.165888

Kc = 0.015444

Therefore, the equilibrium constant for the reaction at 500 K is 0.015444.