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Select the correct answer.

A linear function on a coordinate plane passes through (4, 3), (0, 1), (minus 2, 0), and (minus 4, minus 1) The image of Rightwards White Arrow A linear function on a coordinate plane passes through (minus 5, 3), (minus 2, 0), (0, minus 2), and (3, minus 5)

The slope of the function on the left is multiplied by p, and q is added to the y-intercept to arrive at the function on the right. Which of the following are the values for p and q?

Select the correct answer. A linear function on a coordinate plane passes through-example-1

2 Answers

4 votes

Answer:

D

Explanation:

the slope of the function on the left is
(1)/(2). so, if the slope multiplied by -2 we got -1.

y-intercept is at 1. if 1 plus -3 we got -2

User Marthe
by
7.8k points
1 vote

Answer:


\textsf{D.\quad$p=-2$\;\;and\;\;$q=-3$}

Explanation:

The slope of a line shows the direction and steepness of the line.

The slope of a line can by calculated by using slope formula:


\textsf{Slope\;$(m)=(y_2-y_1)/(x_2-x_1)$}

where (x₁, y₁) and (x₂, y₂) are two points on the line.

Given the left function passes through the points (4, 3) and (0, 1), substitute these into the slope formula to find the slope of the line:


\implies \textsf{Slope}\;(m)=(1-3)/(0-4)=(-2)/(-4)=(1)/(2)

Given the righ-5 function passes through the points (-5, 3) and (-2, 0), substitute these into the slope formula to find the slope of the line:


\implies \textsf{Slope}\;(m)=(0-3)/(-2-(-5))=(-3)/(3)=-1

Given the slope of the function on the left is multiplied by p to arrive at the slope of the function on the right:


\implies (1)/(2)p=-1


\implies 2 \cdot (1)/(2)p=2 \cdot -1


\implies p=-2

The y-intercept is the point at which the line crosses the y-axis.

The left function crosses the y-axis at (0, 1), so its y-intercept is y = 1.

The right function crosses the y-axis at (0, -2), so its y-intercept is y = -2.

Given q is added to the y-intercept of the function on the left to arrive at the y-intercept of the function on the right:


\implies 1+q=-2


\implies 1+q-1=-2-1


\implies q=-3

Solution


\textsf{$p=-2$\;\;and\;\;$q=-3$}

The equations of the functions are:


\textsf{Left\;function:\quad $y=(1)/(2)x+1$}


\textsf{Right\;function:\quad $y=-x-2$}

User Deanmcpherson
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8.5k points