Question 1

Hello guys can someone help me with this, my dead line is too close hehe

Question 2

We will solve all the questions by pythagoras theorem i.e.

$\boxed{ \mathcal{ {H}^(2) = {P}^(2) + {B}^(2) }}$

$\green \implies \red{ \sf{30}^(2) = {x}^(2) + {18}^(2) }$

$\green \implies \red{ \sf{x}^(2) = {30}^(2) - {18}^(2) }$

$\green \implies \red{ \sf{x}^(2) = 900 - 324 }$

$\green \implies \red{ \sf{x}^(2) = 576}$

$\green \implies \red{ \sf \: x= √(576)}$

$\green \implies \red{ \sf \: x= 24}$

$\orange \implies \blue{ \sf \: {14}^(2) = {x}^(2) + {x}^(2) }$

$\orange \implies \blue{ \sf \: {14}^(2) = 2{x}^(2) }$

$\orange \implies \blue{ \sf \: 196= 2{x}^(2) }$

$\orange \implies \blue{ \sf \: 98 = {x}^(2) }$

$\orange \implies \blue{ \sf √(98 )= {x}}$

$\orange \implies \blue{ \sf x = 9.9}$

$\pink \implies \purple{ \sf {x}^(2) = {70}^(2) + {240}^(2) }$

$\pink \implies \purple{ \sf {x}^(2) = 4900 + 57600 }$

$\pink \implies \purple{ \sf {x}^(2) = 62500 }$

$\pink \implies \purple{ \sf x = √(62500) }$

$\pink \implies \purple{ \sf x = 250 }$

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