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Hello guys can someone help me with this, my dead line is too close hehe

Hello guys can someone help me with this, my dead line is too close hehe-example-1

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We are given the measurements:

  • AE = 8m-13
  • PX = 5m+20

Now,


\boxed { \mathcal{ \green{AE = PX}}}

Since, the diagonals of a rectangle are equal..

  • Put the values of AE and PX equal to find m


\pink \implies \purple { \sf8m -13 = 5m + 20 }


\pink \implies \purple { \sf8m -13 - 5x = 20 }


\pink \implies \purple { \sf8m - 5m = 20 + 13 }


\pink \implies \purple { \sf3m = 33 }


\boxed{ \mathfrak { \red{m = 11}}}

#4


\blue \longmapsto \orange{ \tt \: AE = 8m - 13}


\blue \longmapsto \orange{ \tt \: AE = 8(11) - 13}


\blue \longmapsto \orange{ \tt \: AE = 88- 13}


\boxed{ \mathfrak{ \red{AE = 75 \: cm}}}

#5


\blue \longmapsto \orange{ \tt \:PX = 5m+ 20}


\blue \longmapsto \orange{ \tt \:PX = 5(11)+ 20}


\blue \longmapsto \orange{ \tt \:PX = 55+ 20}


\boxed{ \mathfrak{ \red{ PX= 75 \: cm}}}

#6


\boxed{ \mathfrak { \red{m = 11}}}

User Anton Geraschenko
by
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