Question

A system of linear equations is given by these equations:

The solution to this system is (
).
3y2x = -9
y = -2x + 5
Submit

Answer 1

Explanation:

(3, -1) or x=3, y=-1

Explanation:

using substitution for y, the first equation becomes 3(-2x + 5) - 2x = -9

distribution of the 3 gets your equation to be -6x + 15 - 2x = -9

from here you combine like terms to get -8x + 15 = -9

from here it's just a two step equation

subtract 15 from both side to get -8x = -24

divide and get x = 3

substitute x in the equation for y to get y = -2(3) + 5

distribution gets you y = -6 + 5, which makes y = -1

to check your work you can just plug in the variables equivalents in the first equation, which upon doing you can see that the answer is indeed 3, -1

Answer 2

(3, -1) or x=3, y=-1

Explanation:

using substitution for y, the first equation becomes 3(-2x + 5) - 2x = -9

distribution of the 3 gets your equation to be -6x + 15 - 2x = -9

from here you combine like terms to get -8x + 15 = -9

from here it's just a two step equation

subtract 15 from both side to get -8x = -24

divide and get x = 3

substitute x in the equation for y to get y = -2(3) + 5

distribution gets you y = -6 + 5, which makes y = -1

to check your work you can just plug in the variables equivalents in the first equation, which upon doing you can see that the answer is indeed 3, -1