Answer:
Step-by-step explanation:
We can use Ohm's law to determine the voltage drop across a resistor, given its resistance and the power dissipated by it.
Ohm's law states that V = IR, where V is the voltage drop across the resistor, I is the current flowing through it, and R is the resistance of the resistor.
The power dissipated by the resistor can be calculated using the formula P = IV, where P is the power, I is the current, and V is the voltage drop across the resistor.
We are given that the resistance of the resistor is 2.2 kΩ and the power dissipated is 0.1 W.
First, we can calculate the current flowing through the resistor using the formula P = IV. Rearranging this equation, we get I = P/V.
Substituting the given values, we get:
I = P/V = 0.1 W / V
Next, we can use Ohm's law to express the voltage drop across the resistor as V = IR.
Substituting the value of I, we get:
V = IR = (0.1 W / V) x (2.2 kΩ) = 220 V
Therefore, the voltage drop across the 2.2 kΩ resistor is 220 V when it dissipates 0.1 W of power.