If the scale of the model is 4:5, it means that every linear dimension of the model is 4/5 of the corresponding dimension of the full-size prototype.
Let's call x the length of the full-size prototype in feet.
Then, we can set up the following proportion:
4/5 = model length / full-size prototype length
Solving for the full-size prototype length:
full-size prototype length = model length / (4/5) = model length * (5/4)
The length of the model is 4/5 of the full-size prototype length, so:
model length = (4/5) * x
Substituting this into the equation above:
full-size prototype length = model length * (5/4) = (4/5) * x * (5/4)
Simplifying:
full-size prototype length = x
Therefore, the length of the full-size prototype is:
x = (4/5) * x * (5/4) = 90 feet
So, the full-size prototype would be 112.5 feet long.