Answer:
2.338 × 10^-7 N
2.684 × 10^-14 N
Step-by-step explanation:
1
The force of attraction between two objects with masses m1 and m2, separated by a distance r, is given by the formula:
F = G * (m1 * m2) / r^2
where G is the gravitational constant, which has a value of approximately 6.674 × 10^-11 N * m^2 / kg^2.
Using this formula, we can calculate the force of attraction between Carlos and Daisy:
F = 6.674 × 10^-11 * (70.0 kg * 50.0 kg) / (10.0 m)^2
= 2.338 × 10^-7 N
Therefore, the force of attraction between Carlos and Daisy when they are standing 10.0 meters apart is approximately 2.338 × 10^-7 N.
2
The force of attraction between two objects with masses m1 and m2, separated by a distance r, is given by the formula:
F = G * (m1 * m2) / r^2
where G is the gravitational constant, which has a value of approximately 6.674 × 10^-11 N * m^2 / kg^2.
In this case, we have two balls with a mass of 1.0 kg each, separated by a distance of 0.250 km = 250 m. Plugging in these values into the formula above, we get:
F = 6.674 × 10^-11 * (1.0 kg * 1.0 kg) / (250 m)^2
= 2.684 × 10^-14 N
Therefore, the force of attraction between the two balls is approximately 2.684 × 10^-14 N.