Question

3 Harriette and Michael are wrapping presents for their mother's birthday. They have 5 1/3 meters of ribbon and plan to use 3/4 meters to wrap each present. How many presents can they wrap?​

Answer 1

Harriette and Michael can wrap about 61 presents with the given length of ribbon.

Explanation:

To determine the number of presents they can wrap, we need to divide the total length of ribbon by the length of ribbon used to wrap each present.

The length of ribbon used to wrap each present is 3/4 meters.

To convert the mixed number 5 1/3 to an improper fraction, we can multiply the whole number by the denominator of the fraction and add the numerator.

5 1/3 = (5 x 3) + 1/3 = 15 1/3

Now we can divide the total length of ribbon by the length of ribbon used to wrap each present:

(15 1/3) ÷ (3/4) = (46/3) ÷ (3/4)

To divide by a fraction, we can multiply by its reciprocal:

(46/3) ÷ (3/4) = (46/3) x (4/3)

We can simplify this expression by canceling out common factors:

(46/3) x (4/3) = (2 x 23/1) x (4/1 x 3)

Multiplying across, we get:

(2 x 23/1) x (4/1 x 3) = 46 x 4 / 3

Dividing, we get:

46 x 4 / 3 = 184 / 3

So they can wrap 184/3 presents with the given length of ribbon. However, since we can't have a fraction of a present, we need to round the answer to the nearest whole number.

Rounding 184/3 to the nearest whole number gives us:

184/3 ≈ 61.33

So Harriette and Michael can wrap about 61 presents with the given length of ribbon.

Hope this helps! If not, I'm sorry. If you need more help, ask me! :]