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At the start of a reaction the volume of a gas is 3.9L and the temp is 253 K. What will be the volume of the gas at 353 K?

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To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

P₁V₁/T₁ = P₂V₂/T₂

where P₁, V₁, and T₁ are the initial pressure, volume, and temperature of the gas, and P₂, V₂, and T₂ are the final pressure, volume, and temperature of the gas.

In this problem, we are given the initial volume (V₁) and temperature (T₁), and we want to find the final volume (V₂) at a different temperature (T₂). We can assume that the pressure of the gas remains constant.

Plugging in the values we get:

P₁V₁/T₁ = P₂V₂/T₂

Since the pressure is constant, we can simplify this to:

V₁/T₁ = V₂/T₂

Solving for V₂:

V₂ = V₁(T₂/T₁)

Plugging in the values we get:

V₂ = 3.9 L (353 K / 253 K)

V₂ = 5.45 L

Therefore, the volume of the gas at 353 K will be 5.45 L (rounded to two decimal places).