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A pharmacist has an 18% alcohol solution. How much of this solution and how much water must be mixed together to make 10 liters of a 12% alochol solution?

User Falieson
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2 Answers

3 votes

Answer:

6.67L of solution and 3.33L of water

Explanation:

User Agung Pratama
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Let x be the amount of 18% alcohol solution needed, and y be the amount of water needed to make 10 liters of a 12% alcohol solution.

The concentration of the alcohol in the 18% solution is 18%, which means that it contains 18 mL of alcohol per 100 mL of solution.

The concentration of the alcohol in the final 12% solution is 12%, which means that it contains 12 mL of alcohol per 100 mL of solution.

To find the amount of alcohol in the final solution, we can use the equation:

0.12(10) = 0.18x

where 0.12(10) is the total amount of alcohol needed in the final solution, and 0.18x is the amount of alcohol in the 18% solution.

Simplifying this equation, we get:

x = 6.67

This means that we need 6.67 liters of the 18% alcohol solution.

To find the amount of water needed, we can subtract the amount of the 18% alcohol solution from the total volume:

y = 10 - 6.67

y = 3.33

Therefore, we need 6.67 liters of the 18% alcohol solution and 3.33 liters of water to make 10 liters of a 12% alcohol solution.

User Sebastian Ax
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