Question

Find the output global maximum and global minimum values of the function f(x) = x^3- 9x^2 - 32x + 10(A) Interval = -5, 0Global maximum = (B) Interval = 0,9 Global minimum = (C) Interval =-5, 9.Global maximum =Global minimum =

Answer 1

Given the function f:

We want to find its output global maximum and global minimum values.

To do this, we need to find the deritative of the function first:

Now, we're going to set it equal to zero:

Finally, replace the values x=-5, x=0, and the solutions of the previous equation in the original function. The highest value will be the maximum and the lowest value will be the minimum:

The output global maximum at the interval -5,0 is 34.43.