Explanation:
It is not possible for a 9th degree function to have exactly 2 real solutions and 4 imaginary solutions. This is because the complex solutions of a polynomial equation always come in pairs of complex conjugates. Therefore, if a 9th degree polynomial has 4 imaginary solutions, it must also have 4 corresponding complex conjugate solutions, resulting in a total of 8 complex solutions. The polynomial could have 2 real solutions and 7 imaginary solutions or 1 real solution and 8 imaginary solutions, but not 2 real solutions and 4 imaginary solutions.