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PLEASE HELP!! 100 POINTS!! Give one example of how it is possible for a 9th degree function to have 2 real solutions and 4 imaginary.​

User Jbobbins
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Explanation:

It is not possible for a 9th degree function to have exactly 2 real solutions and 4 imaginary solutions. This is because the complex solutions of a polynomial equation always come in pairs of complex conjugates. Therefore, if a 9th degree polynomial has 4 imaginary solutions, it must also have 4 corresponding complex conjugate solutions, resulting in a total of 8 complex solutions. The polynomial could have 2 real solutions and 7 imaginary solutions or 1 real solution and 8 imaginary solutions, but not 2 real solutions and 4 imaginary solutions.

User Tmaster
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