Question

Identify the normal equations of an exponential curve.ΣxY = AΣx + BΣx2 and ΣY = nA + BΣxΣxY = AΣx + BΣx2 and ΣY = A + BΣxΣxY = AΣx - BΣx2 and ΣY = nA + BΣxΣxY = AΣx + BΣx2 and ΣY = nA - BΣx

Answer 1

Given

The normal equations of an exponential curve.



Solution

`The\text{ exponential equation is y=ax}^b`

taking logarithm on both sides, we get

`\begin{gathered} log10y=log10a+blog10x \\ \\ Y=A+bXwhereY=log10y,A=log10a,X=log10x \end{gathered}`

which linear in Y,X

So the corresponding normal equations are

`\begin{gathered} ∑Y=nA+b∑X \\ \\ ∑XY=A∑X+b∑X2 \end{gathered}`

The final answer

Option A