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Use the remainder theorem to find P(a) f(a) = x ^ 3 - 2x ^ 2 - 3x + 6 at a = 2​

Use the remainder theorem to find P(a) f(a) = x ^ 3 - 2x ^ 2 - 3x + 6 at a = 2​
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Use the remainder theorem to find P(a)

f(a) = x ^ 3 - 2x ^ 2 - 3x + 6 at a = 2​

User Mateostabio
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7.6k points

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Hopefully this is what you’re looking for. Not quite sure if P(a) is a new function or a typo.
Use the remainder theorem to find P(a) f(a) = x ^ 3 - 2x ^ 2 - 3x + 6 at a = 2​-example-1
User BenedictWilkins
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