84.3k views
0 votes
CHEMISTRY CHEMISTRY 100 POINTS 100 POINTS MUST BE CORRECT

CHEMISTRY CHEMISTRY 100 POINTS 100 POINTS MUST BE CORRECT-example-1
CHEMISTRY CHEMISTRY 100 POINTS 100 POINTS MUST BE CORRECT-example-1
CHEMISTRY CHEMISTRY 100 POINTS 100 POINTS MUST BE CORRECT-example-2
CHEMISTRY CHEMISTRY 100 POINTS 100 POINTS MUST BE CORRECT-example-3

2 Answers

4 votes

Answer

b) substitution reaction

Steps

Formation of HCI in Friedel-Crafts

The reaction is an example of a type

of reaction called electrophilic

aromatic substitution.

Friedel-Crafts alkylation is a chemical

reaction.

The reaction combines benzene and

chloromethane.

The reaction requires a catalyst called

anhydrous aluminum chloride.

The reaction produces a new

molecule called methylbenzene or

toluene.

Hydrogen chloride is released as a

byproduct.

A hydrogen atom in the benzene

molecule is replaced with a new

molecule, CH3+

The reaction of benzene with chloromethane in the presence of anhydrous aluminum chloride as a catalyst is known as Friedel-Crafts alkylation. The reaction can be represented as:

C6H6 + CH3Cl → C6H5CH3 + HCl

In this reaction, the aluminum chloride acts as a Lewis acid catalyst and helps to activate the chloromethane, allowing it to react with the benzene. The product formed is methylbenzene (toluene) and hydrogen chloride (HCl) is also formed as a byproduct.

The HCl is generated as a result of the reaction between the AlCl3 and the chloromethane. The aluminum chloride (AlCl3) is a strong Lewis acid and readily accepts the chloride ion from the chloromethane molecule to form AlCl4- ion, releasing H+ ion in the process:

AlCl3 + CH3Cl → AlCl4- + CH3+ + HCl

Therefore, the presence of anhydrous aluminum chloride in the reaction mixture leads to the formation of hydrogen chloride as a byproduct.

The reaction between benzene and chloromethane in the presence of anhydrous aluminum chloride as a catalyst is a type of electrophilic aromatic substitution reaction, known as Friedel-Crafts alkylation. In this reaction, the electrophile (CH3+) generated by the reaction of chloromethane with AlCl3 attacks the electron-rich aromatic ring of benzene to form a substituted product (methylbenzene/toluene) while releasing HCl as a byproduct.

The above reaction is an example of a substitution reaction. Specifically, it is an electrophilic aromatic substitution reaction, where the electrophilic species (CH3+) substitutes a hydrogen atom in the benzene ring, leading to the formation of methylbenzene (toluene) as the product. The hydrogen atom is released as hydrogen chloride (HCl) during the reaction.

ChatGPT

User Dybzon
by
7.3k points
2 votes
Answer: d) butanoic acid.
The given compound "OH" contains a hydroxyl (-OH) group attached to a four-carbon chain, which is a characteristic functional group of a carboxylic acid. Based on the number of carbon atoms in the chain, the IUPAC name of the compound is butanoic acid.

Answer: b) substitution reaction.
The reaction of benzene with chloromethane in the presence of anhydrous aluminum chloride is an example of a substitution reaction. In this reaction, the hydrogen atom in benzene is replaced by a methyl group from chloromethane, leading to the formation of the compound 'x' and hydrogen chloride.

Answer: b) 2, 9, 6, 6.
The balanced equation for the combustion of propene is:

C3H6 + 9/2 O2 -> 3 CO2 + 3 H2O

Comparing the stoichiometric coefficients of the reactants and products, we get a=2, b=9/2 (which can be multiplied by 2 to give 9), c=3, and d=3. Therefore, the correct answer is b) 2, 9, 6, 6.
User Jishad P
by
6.3k points