Answer: The length of the rectangle is 14 yd, and the width is 12 yd.
Explanation:
Let l be the length of the rectangle, and w be the width, we get l = w + 2.
Perimeter = 2(l + w)
52 = 2[(w + 2) + w]
52 = 2(w + 2 + w)
52 = 2(2w + 2)
52 = 4w + 4
48 = 4w
12 = w
l = w + 2 = 12 + 2 = 14