Question

during the Electrolysis of a Salt m. a Current OF 0-5A flows for 32m 10. Sec and deposit 0-325-9 what is the Charge • OF Meta Jon (m=65; f=96500]​

Answer 1

2

Step-by-step explanation:

Using m/M=It/nF

0.325/65=0.5×(32×60+10)/96500n

n=62725/31362.5

n=2