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If P = (-2, 2), Q = (3, 4), R = (-2, 5) and S = (2, -8) Find the exact magnitude of vector: QR

If P = (-2, 2), Q = (3, 4), R = (-2, 5) and S = (2, -8) Find the exact magnitude of-example-1

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Answer:

The magnitude or length of a vector QR with points Q(x2, y2) and R(x1, y1) can be calculated using the formula:

|QR| = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Using the given points, we have:

Q = (3, 4), R = (-2, 5)

So,

|QR| = sqrt((3 - (-2))^2 + (4 - 5)^2)

= sqrt(5^2 + (-1)^2)

= sqrt(26)

Therefore, the exact magnitude of vector QR is sqrt(26).

User Jeff Gortmaker
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