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In ΔABC, the measure of ∠C=90°, AC = 7, BA = 25, and CB = 24. What is the value of the cosine of ∠A to the nearest hundredth?

1 Answer

4 votes

Answer:

0.28

Explanation:

In the given right triangle ΔABC, with right angle at C, we can use the cosine formula to find the value of cos(∠A):

cos(∠A) = adjacent/hypotenuse = AC/AB

Using the Pythagorean theorem, we can find the length of the hypotenuse AB:

AB^2 = AC^2 + CB^2

AB^2 = 7^2 + 24^2

AB^2 = 625

AB = 25

Therefore, we can calculate the cosine of ∠A as:

cos(∠A) = AC/AB = 7/25

Rounding to the nearest hundredth, we get:

cos(∠A) ≈ 0.28

Therefore, the value of the cosine of ∠A to the nearest hundredth is 0.28.

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