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A student lifts a 30.0 newton ball 7.00 meters in 5.00 seconds. How many joules of work did the student complete?

User Kevin Aung
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Answer: 210 jouls

Explanation:The work done by the student can be calculated using the formula:

Work = Force x Distance x Cosine(theta)

where Force is the force applied on the ball, Distance is the distance moved by the ball, and theta is the angle between the force and the direction of motion (in this case, theta is 0 because the force is applied in the upward direction, which is the same as the direction of motion).

Since the ball is lifted vertically, the angle between the force and the direction of motion is 0, so cosine(theta) is 1. Therefore, we can simplify the formula to:

Work = Force x Distance

Substituting the given values, we get:

Work = 30.0 N x 7.00 m

Work = 210.0 J

Therefore, the student completed 210.0 joules of work in lifting the ball

User Rosman
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