Question

The initial volume of 345 mL with initial concentration of a 1.6 M NaCI solution is reduced to final volume of 250 mL, what is the final concentration?

M1V1=M2V2


O A. 1.16 M
O B. 53906 M
O C. 2208 M
O D. 2.2 M

Answer 1

We can use the dilution formula to find the final concentration of the NaCl solution:

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Substituting the given values, we get:

(1.6 M)(345 mL) = M2(250 mL)

Simplifying and solving for M2, we get:

M2 = (1.6 M)(345 mL) / (250 mL)

M2 = 2.208 M

Therefore, the final concentration of the NaCl solution is 2.208 M (to three significant figures).