Question

6. What is the area of a rectangle with perimeter 126.6 mm and length 40.4 mm?

Answer 1

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Explanation:

Let's assume the width of the rectangle is "w".

Perimeter of a rectangle = 2(length + width)

Given: Perimeter = 126.6 mm, Length = 40.4 mm

So, 2(40.4 + w) = 126.6

81 + 2w = 126.6

2w = 45.6

w = 22.8

Therefore, the width of the rectangle is 22.8 mm.

Area of a rectangle = length x width

Area = 40.4 mm x 22.8 mm

Area = 922.32 sq. mm

Hence, the area of the rectangle is 922.32 sq. mm.