Answer:
Consider the function f(x) = x^2 - 3x + 2. To find the x-intercepts of this function, we set f(x) equal to zero and solve for x. Thus, we have the equation x^2 - 3x + 2 = 0. Factoring this quadratic equation, we obtain (x-1)(x-2) = 0. Therefore, the x-intercepts of the function are x=1 and x=2. To find the vertex of the parabola, we use the formula x = -b/2a, where a and b are the coefficients of the quadratic equation. In this case, a=1 and b=-3, so the x-coordinate of the vertex is x = 3/2. To find the y-coordinate of the vertex, we substitute this value of x into the original equation to get f(3/2) = 1/4. Therefore, the vertex of the parabola is located at the point (3/2, 1/4).