According to the balanced chemical equation:
NaHCO3 + HCl -> NaCl + H2O + CO2
We can see that for every 1 mole of NaHCO3 that reacts, 1 mole of CO2 is produced. Therefore, if we know the number of moles of CO2 produced, we can calculate the number of moles of NaHCO3 required to produce that amount of CO2.
Given that the sealed container holds 0.0135 moles of CO2, we know that this amount of CO2 is produced by the reaction of 0.0135 moles of NaHCO3.
So, we can use the following equation to calculate the mass of NaHCO3 required:
mass = moles x molar mass
where the molar mass of NaHCO3 is 84.01 g/mol.
mass of NaHCO3 = 0.0135 mol x 84.01 g/mol
mass of NaHCO3 = 1.134 g
Therefore, the mass of NaHCO3 required to generate 0.0135 mol of CO2 is approximately 1.134 grams.